Question

The filament of electric bulb draces a current of 0.4 ampere .Calculate the amount of charge flowing through the filament if the bulb glow for 2 hours .Also calculate number of electons pass?

Answer 1

Answer:

2880 C, 1.80*10²² electrons

Explanation:

I = 0.4 A = 2/5 A

t = 2 hrs = 2*3600s

Q = ?

I = Q/t

Q = It = 2*2*3600/5 = 4*720 = 2880 C

Now, Q = 2880 C, e = 1.6*10⁻¹⁹ C, n = ?

Q = ne

n = Q/e = 2880/1.6*10⁻¹⁹ = 1.80*10²² electrons