The final products formed on the addition of KI to copper sulphate solution are :
(a) K₂SO₄, CuI₂ and I₂
(b) K₂SO₄, Cu₂I₂ and I₂
(c) K₂SO₄ and Cu₂O
(d) K₂SO₄, CuO and I₂
Answers
Answered by
1
Answer:a
Explanation:
Answered by
1
Answer:
The correct option is (b).
Explanation:
Reaction of Copper sulphate (CuSO4) with Potassium iodide (KI) is an example of redox reaction. So, it would not undergo any sort of precipitation or double displacement reaction. The reaction involves oxidizing agent I⁻ and reducing agent Cu²⁺. I⁻ reduces Cu²⁺ to Cu⁺ form and itself get oxidized to I₂.
Therefore the complete reaction is
2CuSO₄+2KI→Cu₂I₂+K₂SO₄+I₂
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