Physics, asked by pravallikamargam39, 7 hours ago

the final velocity of a particle falling freely under gravity is given by v^2-u^2=2gx where x is the distance covered if v=18kmph,g=1000cm s^-2 , x=120cm then u is (n ms^-1)
A 2.4
B 1.2
C 1
D 0.1​

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Answered by akhilsingh5879
1

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