Question

the
Find p(-1), P (-2) and (-3) for each of
following polymonial
Þ(t)= 2+ t + 2t sq - t cube​

Answer 1

Given :

p(t) = 2 + t + 2t² - t³

To find:

1. p(-1)
2. p(-2)
3. p(-3)

Solution :

1. p(-1)

Put value of t = (-1)

p(-1) = 2 + (-1) + 2(-1)² - (-1)³

p(-1) = 2 - 1 + 2(1) - (-1)

p(-1) = 1 + 2 + 1

p(-1) = 4

2. p(-2)

Put value of t = (-2)

p(-2) = 2 + (-2) + 2(-2)² - (-2)³

p(-2) = 2 - 2 + 2(4) - (-8)

p(-2) = 0 + 8 + 8

p(-2) = 16

3. p(-3)

Put value of t = (-3)

p(-3) = 2 + (-3) + 2(-3)² - (-3)³

p(-3) = 2 - 3 + 2(9) - (-27)

p(-3) = -1 + 18 + 27

p(-3) = 44

ANSWER :

1. p(-1) = 4
2. p(-2) = 16
3. p(-3) = 44