Math, asked by Anonymous, 4 months ago

The find vue of A and B


3-√5/3+2√5

Don't Span


No problem Siso

aap PK. me kha se h....Sis​

Answers

Answered by Anonymous
3

\huge\boxed{\fcolorbox{red}{blue}{ QUESTION }}

How much sugar(C12H22O11) will be required if each person on earth is given 100 molecules of sugar? (population of earth=3*10^10)

 \orange{\underline{\textit{\green{\bf{CONCEPT \:used:-}}}}}

IS OF MOLE :-

 \orange{\underline{\textit{\blue{\bf{DEFINITION:- }}}}}

The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). A mole of a substance or a mole of particles is defined as exactly 6.02214076×10^23 particles, which may be atoms, molecules, ions, or electrons.

 \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

sugar(C12H22O11) required for each person on earth :-

GIVEN

100 MOLECULES TO BE GIVEN TO EACH PERSON

POPULATION OF EARTH-->3 \times  {10}^{10}

 \orange{\underline{\textit{\green{\bf{TOTAL\: MOLECULES \:REQUIRED:-}}}}}

PER PERSON REQUIREMENT× POPULATION OF EARTH --->

100 \: molecules  \times 3 \times  {10}^{10}  \\  \\  3 \times  {10}^{12}  =  \: number \: of \: molecules \: required \: in \: total \:

SO ONE MOLE OF SUGAR WEIGHT 342 grams

one mole = 6.022 \times  {10}^{23}  \: molecules \: =342 grams

so one molecules weights -->

 \frac{342}{6.022 \times  {10}^{23} } \: grams

so 3×10^12 molecules weights -->

 \frac{342}{6.022 \times  {10}^{23} }  \times 3 \times  {10}^{12}  \:  \: grams

 \orange{\underline{\textit{\red{\bf{ REQUIRED\; WEIGHT}}}}}

\underline{\blue{170 \times  {10}^{ - 11}  \:  \: grams}}

THANKS FOR THANKING MY ANS

FOLLOW ME FOR MORE ANS.

Similar questions