Question

the
find zeroes
the polynomial
p (x) = x²-6x +8

Answer 1

Step-by-step explanation:

hope it will help you....

Answer 2

Answer: p(x)=x^2 - 6x + 8

                    = x^2 - 2x - 4x + 8                 ( 4 and 2 are the factors of 8)

                   = x(x-2) - 4(x-2)

                    = (x-4)(x-2)

Zeros are :   x-4 = 0          &    x-2 = 0

                     ∴x=4                   ∴x=2

  ∴ The two zeros are 4 and 2

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