Math, asked by Akita4138, 1 day ago

The first 3 terms of an AP y, (3y+1) and (7y-4) find:
I. Value of y
II. 10th term
III. sum of the first 20 terms IV. The first term

Answers

Answered by siddhiharak27
3

Answer:

MAY THIS WILL HELP U

Step by step:

The first three terms of A.P are (3y−1). (3y+5) and (5y+1). Then y equals to _____. 

Given that,

The first 3 terms of A.P. are (3y−1),(3y+5),(5y+1).

 

Therefore,

2(3y+5)=3y−1+5y+1

6y+10=8y

2y=10

y=5

 

Hence, the value of y is 5.

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