The first 3 terms of an AP y, (3y+1) and (7y-4) find:
I. Value of y
II. 10th term
III. sum of the first 20 terms IV. The first term
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Step by step:
The first three terms of A.P are (3y−1). (3y+5) and (5y+1). Then y equals to _____.
Given that,
The first 3 terms of A.P. are (3y−1),(3y+5),(5y+1).
Therefore,
2(3y+5)=3y−1+5y+1
6y+10=8y
2y=10
y=5
Hence, the value of y is 5.
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