The first 4 terms of an AP having the
first term 10 and common difference
3 is
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Given :
- First term (a) = 10
- Common difference (d) = 3
To Find :
- First four terms
Solution :
⇒a1 = a
⇒a1 = 10
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⇒a2 = a + d
⇒a2 = 10 + 3
⇒a2 = 13
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⇒a3 = a + 2d
⇒a3 = 10 + 2(3)
⇒a3 = 10 + 6
⇒a3 = 16
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⇒a4 = a + 3d
⇒a4 = 10 + 3(3)
⇒a4 = 10 + 9
⇒a4 = 19
_____________________
A.P is 10,13,16,19....
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