The first & second stage of two stage rocket
separately weigh 100 kg and 10 kg and contain
800kg and 90kg fuel respectively. If the exhaust
velocity of gases is 2 km/sec then velocity of
rocket after second stage is (nearly)
(log, 5=0.6990) (neglect gravity)
1) 7.8 x 10 m/s 2) 9.3 x 10 m/s
3) 2.4 x 10 m/s
4) 6.1 x 10 m/s
Answers
Answer:
The answer is 7.82 X 10^3 m/s.
Explanation:
The initial velocity of the rocket V0 = 0
Velocity of the rocket after exhaustion of the forst stage is
V = μ ln m0 / m
Here,
m0 = 100 + 10 + 800 +90 = 1000 kg
m = 100 + 10 + 90 = 200 Kg
Thus |V| = 2 ln 5
= 2 x 1.609
= 3.218 Km/s
The second stage becomes operative when the first is detached from it.
μ0 = 3.218 Km/s
m0 = 10 + 90 = 100 Kg
m = 10 Kg
Thus, |V| = 3.22 + 2ln (100 /10)
= 3.22 + 2 X (2.3)
= 7.82 X 10^3 m/s
Answer:
The answer is 7.82 X 10^3 m/s.
Explanation:
The initial velocity of the rocket V0 = 0
V = μ ln m0 / m
Here,
m0 = 100 + 10 + 800 +90 = 1000 kg
m = 100 + 10 + 90 = 200 Kg
Thus |V| = 2 ln 5
= 2 x 1.609
= 3.218 Km/s
μ0 = 3.218 Km/s
m0 = 10 + 90 = 100 Kg
m = 10 Kg
Thus, |V| = 3.22 + 2ln (100 /10)
= 3.22 + 2 X (2.3)
= 7.82 X 10^3 m/s