Question

The first and 3rd term of an AP 3(2)½ and -3(2)½ respectively .The end 2nd term._______

a)0
b)2a
c)-2a
d)2b-2a
pls choose any one answer​

Answer 1

Answer:

0

Step-by-step explanation:

let t1 = 3(2)1/2

and, t3 = -3(2)1/2

since, t2- t1 = t3 - t2

=> t2 - 3(2)1/2 = -3(2)1/2 - t2

=> t2 + t2 = -3(2)1/2 + 3(2)1/2

=> 2t2 = 0

=> t2 = 0