Question

The first and eighth terms of a g.P. Are 3 and 2 respectively, then find the value of 'p' provided it's the product of first eight terms of the corresponding g.P

Answer 1

Answer:

Answer is: $3^4\times2^4$

Step-by-step explanation:

the terms of an G.P. is given by:

$a,ar,ar^2,ar^3,....$

where a denote the first term and r denote the common ratio.

Now we are given:

$a=3$ and $ar^{7}=2$

This means  $r^7=\dfrac{2}{3}$

We are asked to find the product of first eight terms of G.P. i.e we are asked to find the product :

$a\times (ar)\times (ar^2)\times (ar^3)\times (ar^4)\times (ar^5)\times (ar^6)\times (ar^7)=a^8\times r^{28} =a^8\times (r^7)^{4}$

                          $=3^8\times (\dfrac{2}{3} )^{4}=3^4\times2^4$

Hence the product of first eight terms of the corresponding G.P. is: $3^4\times2^4$

Answer 2

Answer:

Answer is: 3^4\times2^4

Step-by-step explanation: