Question

the first and last term of an A..p are 1 and 11 respectively if the sum of its term is 36 the number term is (1) 8 (2) 7 (3) 4 (4) 6​

Answer 1

Answer:

6

Step-by-step explanation:

Using

$sum = \frac{n}{2} (first \: term + \: last \: term)$

we get

$36 = \frac{n}{2} (1 + 11)$

$72 = n(12)$

$n = 6$

Therefore there are 6 terms

Answer 2

Answer:

Sum of terms of AP= (no of terms/2) (1st terms + last terms)

so, 36= n/2 × ( 1+11) [ n= no of terms]

n= 6