The first and last term of an AO are a and l respectively. If S is the sum of all terms of the AP and the common difference is given by l²-a²/k-(l+a), then k =
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Answer:
We have, S=
2
n
(a+l)⇒
a+l
2S
=n ...(1)
Also, l=a+(n−1)d⇒d=
n−1
l−a
=
a+l
2S
−1
l−a
(from (1))
=
2S−(l+a)
l
2
−a
2
∴k=2S
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