the first and last term of an AP are 17 and 350 respectively .if the common diffrrence is 9 how many terms are there and what is their sum
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terms are 38 & sum is 6803
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a = 17
an = 350
n = (an - a)/d + 1
n = (350 - 17)/9 + 1
= 37 + 1
= 38
Hence, there are totally 38 terms.
Sn = S38
S38 = 38/2(17 + 350)
= 19 * 367
= 6973
an = 350
n = (an - a)/d + 1
n = (350 - 17)/9 + 1
= 37 + 1
= 38
Hence, there are totally 38 terms.
Sn = S38
S38 = 38/2(17 + 350)
= 19 * 367
= 6973
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