The first and last term of an AP are 5and 45 respectively. If the sum of all its term is400 find its common difference
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solution : First term (a) is 5 and last term (Tn) is 45
sum of all term (Sn) is 400
Sn= n÷2(a+l)
400 = n(5 + 45 )/2
800= n(50)
n= 16
Tn= a + (n-1)d
45=5 + ( 16-1)d
45 -5 = 15d
40 =15d
d= 40/15= 8/3
I HOPE IT WILL HELP YOU
solution : First term (a) is 5 and last term (Tn) is 45
sum of all term (Sn) is 400
Sn= n÷2(a+l)
400 = n(5 + 45 )/2
800= n(50)
n= 16
Tn= a + (n-1)d
45=5 + ( 16-1)d
45 -5 = 15d
40 =15d
d= 40/15= 8/3
I HOPE IT WILL HELP YOU
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