Question

The first and last term of an AP are 5and45 respectively if the sum of all its terms is 400, find its common different​

Answer 1

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Let n be the total number of terms and d be the common difference.

Given:

First term=a=5

Last term =l=45

Sum of all terms =Sn=400

Sn=n/2[a+l]

400=n/2[5+45]

n/2=400/50

n=16

There are 16 terms in the AP.

Therefore, 45 is the 16th term of the AP.

45=a+(16−1)d

45=5+15d

40=15d

15d=40

d=8/3

Common difference =d=8/3

Common difference is 8/3 and the number of terms are 16.

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