the first and last terms of an A.P are 34 and 64 respectively then the number of terms will be
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Let 1st term be "a" and common difference be "d" then 7 term and 13 term can be written as a+6d=34......equ.(1) a+12d=64......equ.(2) Solve both equ. We get a=4 & d=5 then So, 18 term be a+17d= 4+17 5 = 89 And.
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