The first and last terms of an A.P. are a and b. There are altogether (2n + 1) terms. A new series is
formed by multiplying each of the first 2n terms by the next term. find the sum of the new series.
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first term = a
second term =b
So, common difference=d=b-a
Let nth term is the last term and which is 2a.
Then 2a=a+(n-1)d=a+(n-1)(b-a)
or,a=nb-b-an+a
or,a-a+b=nb-na
or,n(b-a)=b
or,n=b/(b-a)
Now the sum(S)=(a+2a)b/2(b-a)
=3ab/2(b-a) ans.
hope it helps
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