The first and last terms of an ap are a and l respectively. if s be the sum of all terms of an ap then the common difference is
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formula for sum of all terms is n/2(2a+(n-1)d) or n/2(a+last term)
so given a=n/2(a+l) implies n= 2a/(a+1)
we know last term is a+(n-1)d i.e l
therefore l= a+((a-1)/(a+1))d
implies d = (l-a)(a+1)/(a-1)
so given a=n/2(a+l) implies n= 2a/(a+1)
we know last term is a+(n-1)d i.e l
therefore l= a+((a-1)/(a+1))d
implies d = (l-a)(a+1)/(a-1)
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