Question

The first and the last digits of a 3-digit
number differ by 6. Find the difference
between the number and that obtained
by reversing its digits.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Given, difference between two digits is 6.

Therefore, we may say,

(x - y) = 6 [Considering, x & y as the two digits]

Now, let the number be (10x + y)

Hence, the reverse number will be (10y + x)

Now, difference between the number and it’s reverse is,

(10x + y) - (10y + x)

= 10x + y - 10y - x

= 9x - 9y

= 9 (x - y)

= 9 * 6 [Since, (x - y) = 6]

= 54

Hence, the difference between the number and it’s reverse is 54.