the first and the last term of an ap are 41 and 81 respectively if the common difference is 7 how many terms are in the ap
siddhartharao77:
Is ur question correct?Because i am getting Number of terms of an ap = 17.42
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Given:
a = 41= first term
an = 81= last term
common difference is 7
So by the formula ,
an = a + (n-1)d
81= 41+ (n-1)7
81-41=( n-1)7
40= 7n - 7
40+ 7= 7 n
47/7 = n
N = 6 5/7
it may be taken as 7
Is my answer crct ?? if wrong tell me I will edit and am not sure abt this answer
a = 41= first term
an = 81= last term
common difference is 7
So by the formula ,
an = a + (n-1)d
81= 41+ (n-1)7
81-41=( n-1)7
40= 7n - 7
40+ 7= 7 n
47/7 = n
N = 6 5/7
it may be taken as 7
Is my answer crct ?? if wrong tell me I will edit and am not sure abt this answer
Even I got the same answer. But I think it should be in fractions. I think the question is incorrect.
Sorry..It should not be in fractions
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