Question

the first and the last term of an AP are 5 and 45 resp .if the sum of all its term is 400, find the common difference and the number of terms​

Answer 1

Answer:

Let n be the total number of terms and d be the common difference.

Given:

First term=a=5

Last term =l=45

Sum of all terms =S

n

=400

S

n

=n/2[a+l]

400=n/2[5+45]

n/2=400/50

n=16

There are 16 terms in the AP.

Therefore, 45 is the 16th term of the AP.

45=a+(16−1)d

45=5+15d

40=15d

15d=40

d=8/3

Common difference =d=8/3

Common difference is 8/3 and the number of terms are 16.

Answer 2

Answer:

Let n be the total number of terms and d be the common difference.

Let n be the total number of terms and d be the common difference.Given:

Let n be the total number of terms and d be the common difference.Given:First term=a=5

Let n be the total number of terms and d be the common difference.Given:First term=a=5Last term =l=45

Let n be the total number of terms and d be the common difference.Given:First term=a=5Last term =l=45Sum of all terms =S

Let n be the total number of terms and d be the common difference.Given:First term=a=5Last term =l=45Sum of all terms =S n =400