Math, asked by anitashah9367, 9 months ago

The first and the last terms of an A.P are 8 and 350 respectively.if its common difference is 9 ,how many terms are there and what is their sum

Answers

Answered by lokeshgadhi
0

Formula of n= a+(n-1)d

350=8+(n-1)9

350=8+9n-9

9n=351

n=39

now sum=n/2(a+l)

39/2(8+350)

39/2×358=39×179=6981

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Answered by Anonymous
5

Given :

  • First term, a = 8
  • Last term, l = 350
  • Common difference, d = 9

To Find :

  • Number of terms in AP, n = ?
  • Sum of total number of terms in AP,  \sf S_{n} = ?

Solution :

Let, l be the nth term of AP.

\sf : \implies a_{n} = l = 350

Now, we know that :

\Large \underline{\boxed{\bf{ a_{n} = a + ( n - 1 ) d }}}

By, putting values,

\sf : \implies 350 = 8 + ( n - 1 ) \times 9

\sf : \implies 350 = 8 + 9n - 9

\sf : \implies 350 = - 1 + 9n

\sf : \implies 350 + 1 = 9n

\sf : \implies 351 = 9n

\sf : \implies \dfrac{ \cancel{351}^{39}}{\cancel{9}} = n

\sf : \implies 39 = n

\sf : \implies n = 39

\large \underline{\boxed{\sf n = 39}}

Hence, There are 38 number of terms in given AP.

Now, let's find sum of total number of terms in AP.

We know that :

\Large \underline{\boxed{\bf{ S_{n} = \dfrac{n}{2} ( a + a_{n} ) }}}

We have :

  • n = 39
  • a = 8
  •  \sf a_{n} = 350

\sf : \implies S_{39} = \dfrac{39}{2} ( 8 + 350 )

\sf : \implies S_{39} = \dfrac{39}{2} (358)

\sf : \implies S_{39} = \dfrac{39}{\cancel{2}} \times \cancel{358}^{179}

\sf : \implies S_{39} = 39 \times 179

\sf : \implies S_{39} = 6981

\large \underline{\boxed{\sf S_{39} = 6981}}

Hence, There are 39 number of terms in given AP and their sum is 6981.

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