The first and the last terms of an AP are 10 and 361 respectively. If its common difference is 9 then find the number of terms and their total sum
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Step-by-step explanation:
a=10 an=361 d=9
n=? sn=?
an=a+(n-1)d
361=10+(n-1)9
351/9=9n
n=40
sn=s40
s40=n/2(a+an)
=40/2(10+361)
=20(371)
s40=7420
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