The first and the last terms of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum?
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Answer:
an=a+(n-1)d
350=17+(n-1)9
350=17+9n-9
342=9n
Number of terms=342/9
n=38
Sn=n/2[2a+(n-1)d]
S38=19(34+37×9)
S38=19×367
6973 is the answer
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