the first and the second term of a GP .are X^-4 and X^m.If its 8th term is X^52,then find the value of "m".?
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Answered by
14
Answer:
Step-by-step explanation:
a1= 1/x^4
a2=x^m
r=a2/a1
ATQ
a8=ar^7
x^52=1/x^4(1/x^4 *x^(m+4)^7)
x^52=(x^-4(x^(7m+28)))
x^52=(x^7m+28-4)
X^52=x^7m+24
52=7m+24
52-24=7m
28=7m
28/7=m
4=m
Answered by
1
Answer:
m=4..............……………......
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