Question

the first angle of a triangle is doubled its second angle the third angle is 18 degree more than the sum of the first two angles find the three angles of the triangle

Answer 1

let the first angle b 2x
then the second angle b x and third angle b 2x+x+18
Therefore ,by sum of angle of triangle ,we have:
2x+x+2x+x+18=180
6x=162
x=27
therefore the three angles are:27,54,99

Answer 2

let the 3 angles of triangle are a,b,c
given:- a=2b
c= a+b+18
a+b+c=180 degree
2b+b+a+b+18=180
2b+b+2b+b =180-18
6b= 162
b=162/6
= 27

b= 27
a=2b
a = 54
c=a+b+18
c=27+54+18
c=99