The first angle of the triangle is double its second angle. the third angle is 18 degree more than the sum of first two angles. Find the three angles of the triangle
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second angle=x
first angle=2x
sum=2x+x=3x
third angle=3x+18
total angle=180
3x+18+2x+x=180
6x+18=180
6x=162
x=162/6=27
angles= 27,54,99
first angle=2x
sum=2x+x=3x
third angle=3x+18
total angle=180
3x+18+2x+x=180
6x+18=180
6x=162
x=162/6=27
angles= 27,54,99
jithuchly:
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Let the second angle be 'a'
then the first angle will e 2a
the third angle = a+2a+18
= 3a+18
The sum of all the angles of a triangle is 180
so , a+2a+(3a+18)=180
6a+18=180
6a=180-18
=162
a=162/6
Therefore a=27
then the first angle = 27 degree
second angle = 2*27 = 54 degree
third angle = 27+54+18 = 99 degree
then the first angle will e 2a
the third angle = a+2a+18
= 3a+18
The sum of all the angles of a triangle is 180
so , a+2a+(3a+18)=180
6a+18=180
6a=180-18
=162
a=162/6
Therefore a=27
then the first angle = 27 degree
second angle = 2*27 = 54 degree
third angle = 27+54+18 = 99 degree
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