The first correct answer will be marked as brainliest...!!
Attachments:
Answers
Answered by
7
Hey Apurva !
Here is your solution :
Given,
P(x) = ( 2x² + x + k )
g(x) = ( x - 3 )
And , g(x) is a factor of p(x).
Now,
=> ( x - 3 ) = 0
=> x = 3
3 is a factor of g(x).
Using Factor Theorem,
=>P(x) = 2x² + x + k
By putting x = 3,
=> P( 3 ) = 2( 3 )² + 3 + k = 0
=> 2 × 9 + 3 + k = 0
=> 18 + 3 + k = 0
=> 21 + k = 0
=> k = -21.
Hence, the value of k is -21.
==================================
Hope it helps !!
Here is your solution :
Given,
P(x) = ( 2x² + x + k )
g(x) = ( x - 3 )
And , g(x) is a factor of p(x).
Now,
=> ( x - 3 ) = 0
=> x = 3
3 is a factor of g(x).
Using Factor Theorem,
=>P(x) = 2x² + x + k
By putting x = 3,
=> P( 3 ) = 2( 3 )² + 3 + k = 0
=> 2 × 9 + 3 + k = 0
=> 18 + 3 + k = 0
=> 21 + k = 0
=> k = -21.
Hence, the value of k is -21.
==================================
Hope it helps !!
Anonymous:
Thanks for Brainliest !!
Answered by
25
Hey Apurva !
Here is your solution :
Given,
P(x) = ( 2x² + x + k )
g(x) = ( x - 3 )
And , g(x) is a factor of p(x).
Now,
=> ( x - 3 ) = 0
=> x = 3
3 is a factor of g(x).
Using Factor Theorem,
=>P(x) = 2x² + x + k
By putting x = 3,
=> P( 3 ) = 2( 3 )² + 3 + k = 0
=> 2 × 9 + 3 + k = 0
=> 18 + 3 + k = 0
=> 21 + k = 0
=> k = -21.
Hence, the value of k is -21.
==================================
Hope it helps !!
Similar questions