Question

The first four ionization energy values of an element M are 270, 560, 890 and 6072 Kcal.  The formula of its oxide

Answer 1

Answer:

270 =

560 =

890 = At

6072 =

Answer 2

The formula of oxide will be M2O3 as the metal belongs to 13th group of modern periodic table.

●Ionization energy is the energy required to remove an electron from the valence shell of isolated gaseous atom .

●Since maxium change in ionization energy is between the third and fourth which means after removal of third electron the element gets stable noble gas configuration hence fourth ionization energy is maximum .

●So electronic configuration of element will be 2,8,3 as after removal of 3 its get configuration as noble gas hence rapidly the fourth ie is maximum .

●Configuration 2,8,3 is of Aluminum hence metal is aluminium nd oxide formula is Al2O3.