The first four moments of a distribution about x=2 are 1,2.5,5.5 and 16.calculate the four moments about zero
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Answer:
Given, x = 5.
₁²=7, 42²=66, u3²=642, 4¹= 6754
Central moments,
42=-42²-(42¹)² = 66-(7)² = 66-49 43=u3¹-3(42) (u₂²) + 2 (₁²) 3
= 642-3(66) (7) + 2 (7) ³
= 642-1386 +686
<= -58
LA SUA-4 của Cus)+ 6u12)z) - 3 của 4 = = 6754-4X7X642+ 6 (7²) X66-3674) 979
Now, Y₁ = μ3² - (-58) 2 = 3364 4913 =0.6847
23 (17)3
=
979
(17) 2
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