Question

The first four terms of an A.P. are 1, 9, a and b. Find​

Answer 1

Answer:

Here a=10 and d=10.

Now, nth term =a n=a+(n−1)d

∴t¹=a=10

t²=a+d=10+10=20

t³=a+2d=10+2×10=30

t⁴=a+3d=10+3×10=40

Thus, the first four terms of given AP are 10,20,30,40.

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