Question

The first four terms of an A.P.having the first term -7 and common difference 3 are

Answer 1

Given , the first term= 7

common difference =3

first four terms would be a1=7

second term a1+d=7+3=10

third term would be a1+2d = 7+2(3) = 13

fourth term would be a1+3d = 7+3(3) = 15

so the first four terms would be 7, 10 ,13 ,15

Answer 2

GivEn:-

• First term of AP (a) = -7

• Common difference (d) = 3

To find:-

• First four terms of AP.

SoluTion:-

As we know that,

• First term of AP (a) = -7

• Second term $\sf ( a_2 )$ = a + d = -7 + 3 = -4

• Third term $\sf ( a_3 )$ = a + 2d = -7 + 2 × 3 = -7 + 6 = -1

• Fourth term $\sf ( a_4 )$ = a + 3d = -7 + 3 × 3 = -7 + 9 = 2

We know that,

$\sf a, a_2 , a_3 , a_4 ,.....a_n$

Hence, Required AP is,

➟ -7, -4, -1, 2,.....$\sf a_n$

━━━━━━━━━━━━━━━

Additional Information:-

Formula related to AP -

★ To find $\sf a_n$ term of AP,

⠀⠀⠀✩ $\sf a_n = a + (n - 1)d$

★ To find Sum of n terms $\sf( S_n )$ of AP,

⠀⠀⠀✩ $\sf S_n = \dfrac{n}{2} \bigg( 2a + (n - 1)d \bigg)$

━━━━━━━━━━━━━━━

⠀⠀⠀⠀⠀⠀⠀