Question

The first four terms of an AP when a=2 and d= −1, is _​

Answer 1

Answer:

a=2, d=(-1)

a1=2

a2=a1+d=2+(-1)=2-1=1

a3=a2+d=1+(-1)=1-1=0

a4=a3+d=0+(-1)=0-1=(-1)

Therefore, The first four terms of an AP when a=2 and d= −1, is 2, 1, 0, (-1).