Question

*The first four terms of AP for which a = -3, d = 4 are……….*​

Answer 1

Required Answer :-

nth term of an AP is given by ,

$\\ \large\star \: {\boxed{\purple{\sf{a_n = a + (n - 1)d}}}}$

Here ,

• a is first term
• d is common difference

We are given that ,

• First term = -3
• common difference = 4

Calculating second term of given AP ;

➙ a₂ = a + (2 - 1) d

➙ a₂ = -3 + 1(4)

➙ a₂ = - 3 + 4

➙ a₂ = 1

Calculating thrid term of given AP ;

➙ a₃ = a + (3-1)d

➙ a₃ = -3 + 2(4)

➙ a₃ = -3 + 8

➙ a₃ = 5

Similarly calculating the fourth term of given AP ;

➙ a₄ = a + (4 - 1)d

➙ a₄ = - 3 + 3(4)

➙ a₄ = - 3 + 12

➙ a₄ = 9

Hence ,

• The First four terms of gievn AP are - 3 , 1 , 5 and 9.

Answer 2

$\Huge\underline{\overline{\mid{\green{Answer}}\mid}}$

term of an AP is given by

* an = a + (n – 1)d

Here,

• a is first term • d is common difference

We are given that,

• First term = -3 • common difference = 4

Calculating second term of given AP;

- az = a +(2-1) d

- az = -3 + 1(4)

- a, =- 3 + 4

- az = 1

Calculating thrid term of given AP;

- az = a + (3-1)d

- az = -3 + 2(4)

- az = -3 + 8

- az = 5

Similarly calculating the fourth term of given AP;

- a4 = a + (4 - 1)d

- a4 = - 3 + 3(4)

- a4 = - 3 + 12

- - a4 = 9

The First four terms of gievn AP are - 3,1,5 and 9.

$\Huge \boxed{ \colorbox{lime}{hope \: this \: helps}}$