the first four terms of geometric progression are 0.5,1,2,and 4. Find the smallest number of terms that will give a sum greater than 1000000
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Hlo bro here is your solution
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Let the sum of the four terms of the geometric series be a+ar+ar
2
+ar
3
and r>0
Given that a+ar=8 and ar
2
+ar
3
=72
Now, ar
2
+ar
3
=r
2
(a+ar)=72
⇒r
2
(8)=72∴r=±3
Since r>0, we have r=3.
Now, a+ar=8⇒a=2
Thus, the geometric series is 2+6+18+54.
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