Chemistry, asked by UnbeatableGamer, 6 months ago

the first IE of S is lower than that of P, but the second IE of S is higher than P. explain

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Answered by saivarnikal
0

Answer:

Since the 3p electrons in sulfur (that sulfur would lose) are paired, sulfur has more electron repulsion in those orbitals than phosphorus does, so it takes less energy input to remove an electron from sulfur. Hence, since the ionization occurs more easily, the ionization energy is smaller.

Explanation:

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