Chemistry, asked by Hasanat6209, 1 year ago

The first (IE₁) and second (IE₂) ionisation energies (kJ/mol) of a few elements designated by Roman numerals are given below. Which of these would be an alkali metal?
(a) I
(b) II
(c) III
(d) IV

IE₁
2372
520
900
16803

IE₂
5251
7300
1760
380

Answers

Answered by aditimajumder18
4

Answer:(b) ll - I.E1- 520

I.E2- 7300

Explanation:

As outermost electronic configuration of alkali metals is ns1 and also there size Are larger in their respective periods so their size are larger in their respective periods so there 1st I.E will be lowest among the given options. As 2nd electron is to be removed from the complete shell or noble gas core, so the 2nd I.E must be the highest among the opinions.

Similar questions