The first ionization energy of carbon atom is greater than that of boron atom where as the reverse is true for the second ionization energy.
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Electronic Configuration of C : 1s2, 2s2, 2p2
Electronic Configuration of B : 1s2, 2s2, 2p1
The first ionization energy of C will be higher than that of B, this is simply because the size of C is smaller than that of B. Due to the smaller size of C atom, the valence electron of atom feels greater nuclear charge as compare to the valence electron of B. Due to the greater nuclear force, it requires higher energy to remove the valence electron of C atom as compare to that of B. this can also be justified by the trend of variation of ionization energy along the period.
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Electronic Configuration of C : 1s2, 2s2, 2p2
Electronic Configuration of B : 1s2, 2s2, 2p1
The first ionization energy of C will be higher than that of B, this is simply because the size of C is smaller than that of B. Due to the smaller size of C atom, the valence electron of atom feels greater nuclear charge as compare to the valence electron of B. Due to the greater nuclear force, it requires higher energy to remove the valence electron of C atom as compare to that of B. this can also be justified by the trend of variation of ionization energy along the period.
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Thank you
HOPE IT HELPS..!
Answered by
1
The first ionization energy of carbon atom is greater than that of boron atom where as the reverse is true for the second ionization energy.
⚪ BECAUSE ⚪
1. THE first ionization of the C will be higher than the B .
2. Due to the less ionization electronic of atom nuclear geela greater charge.
⚪ BECAUSE ⚪
1. THE first ionization of the C will be higher than the B .
2. Due to the less ionization electronic of atom nuclear geela greater charge.
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