Question

The first ionization enthalpy of an atom is 9.3 electrons volts. The energy required for the following process will be M M+2 22e_​

Answer 1

Answer:

Explanation:

ΔE=E  

2

​  

−E  

1

​  

 

⇒ΔE=−  

2  

2

 

1.312×10  

6

 

​  

−(−  

1

1.312×10  

5

 

​  

)(∵E  

n

​  

=−  

n  

2

 

E  

1

​  

 

​  

)

⇒ΔE=9.84×10  

5

Jmol  

−1