Question

The first ionization potential of na is 5.1 ev the value of electron gain enthalpy of na+ will be

Answer 1

Answer:

-5.1 ev

Explanation:

Na ------> Na+ + e^- ( First Ionisation Enthalpy )

Na+ + e^- ------> Na. ( Electron Gain Enthalpy of Na + )

Now, because reaction is reverse

Electron Gain Enthalpy of Na+ = -5.1 ev.

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