Question

The first ionizations
energy of Na is 495.9
KJ/mole, what is the
longest wave length of
light that could remove
an electron from Na?(with proper steps please​

Answer 1

Answer:

a) $2.41*{10}^{-7}$

Explanation:

Ionization energy of Na is 495.9KJ/mole

1 mole= 495.9KJ

1 atom= 495.9KJ/Na

         = 495.9/6.023*10^23 = hC/λ

λ=$\dfrac{6.023*{10}^{23}}{495.9*6.626*{10}^{34}*3*{10}^{8}}$

 = $2.41*{10}^{-7}$

Answer 2

Answer:

Answer:

a) 2.41*{10}^{-7}2.41∗10

−7

Explanation:

Ionization energy of Na is 495.9KJ/mole

1 mole= 495.9KJ

1 atom= 495.9KJ/Na

= 495.9/6.023*10^23 = hC/λ

λ=\dfrac{6.023*{10}^{23}}{495.9*6.626*{10}^{34}*3*{10}^{8}}

495.9∗6.626∗10

34

∗3∗10

8

6.023∗10

23

= 2.41*{10}^{-7}2.41∗10

−7

hope it helps you dear ❣️