Chemistry, asked by gopisairamgopi9260, 11 months ago

The first order rate constant for the decomposition of N₂O₅
is 6.2 × 10⁻⁴ sec⁻¹. The half life period for this decomposition
in seconds is
(a) 1117.7 (b) 111.7 (c) 223.4 (d) 160.9

Answers

Answered by Fatimakincsem
1

The half life period for this decomposition  in seconds is 1117.7 seconds

Option (A) is correct.

Explanation:

We are given that

The decomposition of N2O5 = 6.2 × 10⁻⁴ sec⁻¹.

The half life = T

Solution:

Half life can be calculated using the given formula.

t 1/2 = 0.693 / k = 0.693 / 6.2 × 10^−4

t 1/2 = 1117.7 seconds

Thus the half life period for this decomposition  in seconds is 1117.7 seconds

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