Math, asked by punya69, 2 months ago

The first passenger is walking from point A to point B and back, and the second
passenger is walking from point B to point A and back. First time they meet 8 km
from point A and second time they meet 6 km from point B. Find the distance
between the points.

ANS NOW..SPAM ANS WILL GET REPORTED​

Answers

Answered by santoshkumarsingh291
21

Step-by-step explanation:

I found a more logical and fast way for me.

5h is approximately the time needed for B to do PQ.

In 5h A arrived at (3*5 km), so A is impossible.

E is impossible too because of 22>21 and in this option, B would not have returned to meet A.

Now they differ from each other just 6 km (from 15 km to 21 km). in 1 more hour, A will be at 18 km and B 21-4= 17km.

So they should have met between 17 and 18 km.

Answer C, IMO.

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