Question

the first positive term of AP - 11 - 8 - 5​

Answer 1

A.P= -11,-8,-5

a= (-11)

a= (-11)d=3

using formulae

0= a+(n-1)d

0=( -11 )+(n-1)3

11 = 3n-3

3n=14

n= 14/3

n = 4.67

therefore ,

$\longrightarrow$n=5

hence ,

$\sf\pink{ first\:positive\:term\:of \:the\:following\:A.P\:=\:5}$

Answer 2

ANSWERED

A.P= -11,-8,-5

a= (-11)

a= (-11)d=3

Using Formula

0= a+(n-1)d

0= a+(n-1)d0=( -11 )+(n-1)3

0= a+(n-1)d0=( -11 )+(n-1)311 = 3n-3

0= a+(n-1)d0=( -11 )+(n-1)311 = 3n-33n=14

0= a+(n-1)d0=( -11 )+(n-1)311 = 3n-33n=14n= 14/3

0= a+(n-1)d0=( -11 )+(n-1)311 = 3n-33n=14n= 14/3n = 4.67

therefore ,

\longrightarrow⟶ n=5

hence ,

\sf\pink{ first\:positive\:term\:of \:the\:following\:A.P\:=\:5}firstpositivetermofthefollowingA.P=5

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