Question

the first, second and fourth terms of the proportion are 3, 7, 42 find the third term. ​

Answer 1

Answer:

Step-by-step explanation:

Let the the third term be x

So,

First term =3

Second term=7

Fourth term=42

By the question,

First term:Second term::Third term:Fourth term

3:7::x:42

As,

Product of extremes=Product of means

3×42=7×x

3×42/7=x

3×6=x

18=x

Hence,Third term is 18

Answer 2

Answer:

18.

Step-by-step explanation:

Let the third term be: x

First term: 3

Second term: 7

Forth term: 42

3 : 7 :: x : 42

→3/7 = x/42

{By Cross Multiplication or Transposing 7 to RHS and 42 to LHS, we get...}

→3(42) = 7x

→126 = 7x

{Transposing 7 to LHS...}

→126/7 = x

→18 = x

→x = 18

Third term: 18

Checking the Conditions...

First term: 3

Second term: 7

Third term: x → 18

Forth term: 42

Proportion obtained: 3 : 7 :: 18 : 42

→ 3/7 = 18/42

→ 3/7 = 3/7

{Condition Satisfied...}

Hence, the third term is 18.

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