Question

The first second and last terms of an AP are 101,111 and 2001...

Answer 1

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Answer 2

hey...!!

here is ur answer...

First term ===== 101
Second term == 111
and last term == 2001.

So, Tn == a + ( n - 1 ) d

2001 == 101 + ( n - 1 ) 10

2001 == 101 + 10n - 10

2001 == 10n + 91

2001 - 91 === 10n

1910 ==== 10n

n ==== 191


hope it helps u...!!!!