Question

the first,second and last terms of an ap are p,q,2p respectively.Show that its sum is (3pq)/2(q-p)

Answer 1

given that the first term (a) is p and second term is q.

so dommon differnce= (q-p)

the nth term or the last term= 2p

a+(n-1)d = 2p

p+(n-1)(q-p)=2p

(n-1)(q-p)=2p-p

qn-q-pn+p=p

n(q-p)-q=p-p

n=q/(q-p)

sum of n terms= n/2(a+l)

q/(q-p)/2{p+2p}

q/2(q-p){3p}

{3pq}/[2/(q-p)]

hope it helps

Answer 2

Answer:

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