Question

The first second and middle term of an AP are a, b, c respectively. Sum of all terms is​

Answer 1

Answer:

is given that middle form is 0.

for middle term to exist we should have n→ odd

Now,

c = b−a

Also,

c = a + (n + 1 /a) (b - a)

c = a + (n + 1 /a) (a - b)

2c = 2a (n - 1) (b - a)

n - 1 = 2c - 2a/b - a ⇒ n = 2c + b - 3a/ b - a

Now, sum of terms

= n/a [2a(n−1)d]

Answer 2

Answer:

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