Question

The first, second and third I.E of Al are 577, 1816 and 2744 kJ/mol. What is the amount of

energy required to convert one mole of Al into Al3+ ion​

Answer 1

Answer:

51.40 KJ

Explanation:

Given AI - AI3 +3e

for 270×10-3 mole of AI(g)

27

therefore energy =(578+1817 +2745) ×(0.01)=51.40KJ